What is the tangent of y=4+xsqrt(x),(1,5) ?

The tangent of y=4+xsqrt(x),(1,5) is y= 3/2 x+7/2

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tangent of y=4+xsqrt(x),(1,5)

tangent of

y = 4 + x x, (1, 5)

y = \frac{3}{2} x + \frac{7}{2}

Solution steps

Find the slope of

y = 4 + x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = 4 + x x

(1, 5) : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(1, 5) : y = \frac{3}{2} x + \frac{7}{2}

y = \frac{3}{2} x + \frac{7}{2}

x \to 2 lim (x^{4} - 8)

y^{^{''}} + y^{^{'}} - 6 y = 12 x - 50 sin (x)

\frac{d ^{2}}{d x ^{2}} (cos (7 x))

y^{^{'}} = 3 x (y + 4)^{2}

f (t) = t - 4

What is the tangent of y=4+xsqrt(x),(1,5) ?
The tangent of y=4+xsqrt(x),(1,5) is y= 3/2 x+7/2