What is the sum from i=1 to infinity of 8(5/6)^{i-1} ?

The sum from i=1 to infinity of 8(5/6)^{i-1} is converges

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sum from i=1 to infinity of 8(5/6)^{i-1}

i = 1 \sum \infty 8 (\frac{5}{6})^{i - 1}

converges

Solution steps

i = 1 \sum \infty 8 (\frac{5}{6})^{i - 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 8 \cdot i = 1 \sum \infty (\frac{5}{6})^{i - 1}

Apply Series Ratio Test:

converges

= 8 converges

= converges

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What is the sum from i=1 to infinity of 8(5/6)^{i-1} ?
The sum from i=1 to infinity of 8(5/6)^{i-1} is converges