What is the derivative of-2e^{4x} ?

The derivative of-2e^{4x} is -8e^{4x}

What is the first derivative of-2e^{4x} ?

The first derivative of-2e^{4x} is -8e^{4x}

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\frac{d}{d x} (- 2 e^{4 x})

- 8 e^{4 x}

Solution steps

\frac{d}{d x} (- 2 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - 2 e^{4 x} \cdot 4

Simplify

= - 8 e^{4 x}

\int \frac{1}{5 ( 2 x - 1 )} d x

f (x) = x x

x \cdot cos (x), 1

x \to 3 lim (\frac{x ^{2} - 9}{3})

y = 11 - 6 e^{x}, (0, 5)

What is the derivative of-2e^{4x} ?
The derivative of-2e^{4x} is -8e^{4x}
What is the first derivative of-2e^{4x} ?
The first derivative of-2e^{4x} is -8e^{4x}