What is area 2y=3sqrt(x),2y+3x=6,y=-3 ?

The answer to area 2y=3sqrt(x),2y+3x=6,y=-3 is No Solution

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area 2y=3sqrt(x),2y+3x=6,y=-3

area

2 y = 3 x, 2 y + 3 x = 6, y = - 3

No Solution

Solution steps

Isolate

y

for

2 y = 3 x : y = \frac{3 x}{2}

Isolate

y

for

2 y + 3 x = 6 : y = \frac{6 - 3 x}{2}

f_{1} (x) = \frac{3 x}{2}

f_{2} (x) = \frac{6 - 3 x}{2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{3 x}{2} = \frac{6 - 3 x}{2} : x = 1

\frac{3 x}{2} = - 3 :

No Solution for

x \in R

\frac{6 - 3 x}{2} = - 3 : x = 4

Curves not bounded

= No Solution

f (x) = \frac{2 x ^{2} - 5 x}{3 x + 5}

\int_{- 5}^{5} x d x

\frac{d y}{d x} = \frac{4 y ^{2} - x ^{4}}{4 x y}

tan (7 x)

\int 4 (x - 1) ln (x - 1) d x

What is area 2y=3sqrt(x),2y+3x=6,y=-3 ?
The answer to area 2y=3sqrt(x),2y+3x=6,y=-3 is No Solution