What is the d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) ?

The d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) is (t^2)/((t^3+s)^{2/3)}+1/(3(s^3+t)^{2/3)}

What is the first d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) ?

The first d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) is (t^2)/((t^3+s)^{2/3)}+1/(3(s^3+t)^{2/3)}

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\frac{t ^{2}}{( t ^{3} + s ) ^{\frac{2}{3}}} + \frac{1}{3 ( s ^{3} + t ) ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{t ^{2}}{( t ^{3} + s ) ^{\frac{2}{3}}} + \frac{1}{3 ( s ^{3} + t ) ^{\frac{2}{3}}}

\frac{d}{d x} (ln (2 x^{2} + 5))

\int (1 + x + x^{2} + x^{3}) d x

\frac{d}{d x} (a sin (a x))

\int \frac{( 5 x ^{2} - 12 )}{( x ^{2} - 6 x + 13 ) ^{2}} d x

n = 1 \sum \infty \frac{1}{1 + n}

What is the d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) ?
The d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) is (t^2)/((t^3+s)^{2/3)}+1/(3(s^3+t)^{2/3)}
What is the first d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) ?
The first d/(dt)(\sqrt[3]{t^3+s}+\sqrt[3]{s^3+t}) is (t^2)/((t^3+s)^{2/3)}+1/(3(s^3+t)^{2/3)}