What is the integral of (-3)/(x^2) ?

The integral of (-3)/(x^2) is 3/x+C

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integral of (-3)/(x^2)

\int \frac{- 3}{x ^{2}} d x

\frac{3}{x} + C

Solution steps

\int \frac{- 3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 3 (- \frac{1}{x})

Simplify

- 3 (- \frac{1}{x}) : \frac{3}{x}

= \frac{3}{x}

Add a constant to the solution

= \frac{3}{x} + C

y^{^{'}} = y cos (x)

y^{^{'}} + \frac{y}{x} = y^{2}

\frac{\partial}{\partial y} (50 x + 400 - 50 y)

\int (e^{x} cos (y)) d x

8 e^{- x} + 1