What is the derivative of 8e^{-x}+1 ?

The derivative of 8e^{-x}+1 is -8e^{-x}

What is the first derivative of 8e^{-x}+1 ?

The first derivative of 8e^{-x}+1 is -8e^{-x}

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derivative of

8 e^{- x} + 1

- 8 e^{- x}

Solution steps

\frac{d}{d x} (8 e^{- x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{- x}) + \frac{d}{d x} (1)

\frac{d}{d x} (8 e^{- x}) = - 8 e^{- x}

\frac{d}{d x} (1) = 0

= - 8 e^{- x} + 0

Simplify

= - 8 e^{- x}

\frac{d}{d x} (ln (\frac{6 - x}{6 + x}))

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x^{^{''}} + x^{^{'}} + 2 x = 4 e^{2 t}

\frac{d}{d x} (x^{x^{\frac{1}{2}}})

What is the derivative of 8e^{-x}+1 ?
The derivative of 8e^{-x}+1 is -8e^{-x}
What is the first derivative of 8e^{-x}+1 ?
The first derivative of 8e^{-x}+1 is -8e^{-x}