What is the sum from n=1 to infinity of 8/(pi^n) ?

The sum from n=1 to infinity of 8/(pi^n) is converges

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sum from n=1 to infinity of 8/(pi^n)

n = 1 \sum \infty \frac{8}{π ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{8}{π ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 8 \cdot n = 1 \sum \infty \frac{1}{π ^{n}}

Apply Series Ratio Test:

converges

= 8 converges

= converges

\int sec^{2} (θ) + 7 d θ

y = \frac{5}{6} x^{2}, y = \frac{11}{6} - x^{2}

\frac{d}{d x} (e^{r x} r)

f (x) = x^{2} - 5 x + 5, at x = 6

x^{2} cos (x), 0.1

What is the sum from n=1 to infinity of 8/(pi^n) ?
The sum from n=1 to infinity of 8/(pi^n) is converges