What is the tangent of y=2sqrt(x^3)-x^2+4/x ,(4,1) ?

The tangent of y=2sqrt(x^3)-x^2+4/x ,(4,1) is y=-9/4 x+10

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tangent of y=2sqrt(x^3)-x^2+4/x ,(4,1)

tangent of

y = 2 x^{3} - x^{2} + \frac{4}{x}, (4, 1)

y = - \frac{9}{4} x + 10

Solution steps

Find the slope of

y = 2 x^{3} - x^{2} + \frac{4}{x} : \frac{d y}{d x} = 3 x - 2 x - \frac{4}{x ^{2}}

Compute the slope of

y = 2 x^{3} - x^{2} + \frac{4}{x}

(4, 1) : m = - \frac{9}{4}

Find the line with slope m=

- \frac{9}{4}

and passing through

(4, 1) : y = - \frac{9}{4} x + 10

y = - \frac{9}{4} x + 10

x y^{^{''}} + y^{^{'}} = 4 x

y^{^{'}} = 2 (1 + y^{2})

x \to 0 - lim (\frac{5}{2 x})

e^{x} + x e^{x}

\int (4 x - 3 x^{5} + (1.5)^{x}) d x

What is the tangent of y=2sqrt(x^3)-x^2+4/x ,(4,1) ?
The tangent of y=2sqrt(x^3)-x^2+4/x ,(4,1) is y=-9/4 x+10