What is the derivative of e^x+xe^x ?

The derivative of e^x+xe^x is 2e^x+e^xx

What is the first derivative of e^x+xe^x ?

The first derivative of e^x+xe^x is 2e^x+e^xx

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derivative of

e^{x} + x e^{x}

2 e^{x} + e^{x} x

Solution steps

\frac{d}{d x} (e^{x} + x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (x e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

= e^{x} + e^{x} + e^{x} x

Simplify

= 2 e^{x} + e^{x} x

\int (4 x - 3 x^{5} + (1.5)^{x}) d x

y = x^{4} + 2 e^{x}, (0, 2)

f (x) = e^{0} (8 - 7 (0) + 5 (0)^{2})

\frac{d}{d x} (5 e)

\frac{\partial}{\partial y} ((e^{x} + e^{y})^{3})

What is the derivative of e^x+xe^x ?
The derivative of e^x+xe^x is 2e^x+e^xx
What is the first derivative of e^x+xe^x ?
The first derivative of e^x+xe^x is 2e^x+e^xx