What is the tangent of f(x)=sqrt(7x+11),(2,5) ?

The tangent of f(x)=sqrt(7x+11),(2,5) is y= 7/10 x+18/5

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tangent of f(x)=sqrt(7x+11),(2,5)

tangent of

f (x) = 7 x + 11, (2, 5)

y = \frac{7}{10} x + \frac{18}{5}

Solution steps

Find the slope of

f (x) = 7 x + 11 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 11}

Compute the slope of

f (x) = 7 x + 11

(2, 5) : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(2, 5) : y = \frac{7}{10} x + \frac{18}{5}

y = \frac{7}{10} x + \frac{18}{5}

y^{^{'}} = t y - 2 t - 2

\frac{\partial}{\partial x} (\frac{x}{2 y})

y^{^{''}} + 4 y^{^{'}} + 20 y = - 3 sin (2 x)

\frac{d}{d x} (\frac{ln ( x ^{2} + 1 )}{3 x + 1})

1 + ln (x) + \frac{y}{x} d x = (8 - ln (x)) d y

What is the tangent of f(x)=sqrt(7x+11),(2,5) ?
The tangent of f(x)=sqrt(7x+11),(2,5) is y= 7/10 x+18/5