What is (\partial)/(\partial x)(2+x+ye^y) ?

The answer to (\partial)/(\partial x)(2+x+ye^y) is 1

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(\partial)/(\partial x)(2+x+ye^y)

\frac{\partial}{\partial x} (2 + x + y e^{y})

1

Solution steps

\frac{\partial}{\partial x} (2 + x + y e^{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y e^{y})

\frac{\partial}{\partial x} (2) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y e^{y}) = 0

= 0 + 1 + 0

Simplify

= 1

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What is (\partial)/(\partial x)(2+x+ye^y) ?
The answer to (\partial)/(\partial x)(2+x+ye^y) is 1