What is the derivative of ln(2x^2+3) ?

The derivative of ln(2x^2+3) is (4x)/(2x^2+3)

What is the first derivative of ln(2x^2+3) ?

The first derivative of ln(2x^2+3) is (4x)/(2x^2+3)

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\frac{d}{d x} (ln (2 x^{2} + 3))

\frac{4 x}{2 x ^{2} + 3}

Solution steps

\frac{d}{d x} (ln (2 x^{2} + 3))

Apply the chain rule:

\frac{1}{2 x ^{2} + 3} \frac{d}{d x} (2 x^{2} + 3)

= \frac{1}{2 x ^{2} + 3} \frac{d}{d x} (2 x^{2} + 3)

\frac{d}{d x} (2 x^{2} + 3) = 4 x

= \frac{1}{2 x ^{2} + 3} \cdot 4 x

Simplify

\frac{1}{2 x ^{2} + 3} \cdot 4 x : \frac{4 x}{2 x ^{2} + 3}

= \frac{4 x}{2 x ^{2} + 3}

\int 8 x^{\frac{3}{5}} + 7 x^{- \frac{4}{5}} d x

1 + e^{- t}

\frac{4 x - 3}{x}

y^{^{''}} - \frac{3}{x} y^{^{'}} - \frac{4}{x ^{2}} y = 0

\frac{\partial}{\partial x} (17 x^{3} y^{2})

What is the derivative of ln(2x^2+3) ?
The derivative of ln(2x^2+3) is (4x)/(2x^2+3)
What is the first derivative of ln(2x^2+3) ?
The first derivative of ln(2x^2+3) is (4x)/(2x^2+3)