What is the derivative of ln(x)+1 ?

The derivative of ln(x)+1 is 1/x

What is the first derivative of ln(x)+1 ?

The first derivative of ln(x)+1 is 1/x

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derivative of

ln (x) + 1

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (1) = 0

= \frac{1}{x} + 0

Simplify

= \frac{1}{x}

((sin (x))^{2})^{^{'}}

4 (\frac{1}{s ^{3}})

n = 0 \sum \infty \frac{n ^{2}}{5 n}

6 x^{4}

\frac{\partial}{\partial u} (w arctan (uv))

What is the derivative of ln(x)+1 ?
The derivative of ln(x)+1 is 1/x
What is the first derivative of ln(x)+1 ?
The first derivative of ln(x)+1 is 1/x