What is the solution for (dy)/(dx)-7y=xe^{2x} ?

The solution for (dy)/(dx)-7y=xe^{2x} is y=-(e^{2x}(5x+1))/(25)+c_{1}e^{7x}

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(dy)/(dx)-7y=xe^{2x}

\frac{d y}{d x} - 7 y = x e^{2 x}

y = - \frac{e ^{2 x} ( 5 x + 1 )}{25} + c_{1} e^{7 x}

Solution steps

\frac{d y}{d x} - 7 y = x e^{2 x}

Solve linear ODE:

y = - \frac{e ^{2 x} ( 5 x + 1 )}{25} + c_{1} e^{7 x}

y = - \frac{e ^{2 x} ( 5 x + 1 )}{25} + c_{1} e^{7 x}

\frac{d}{d x} (\frac{4 x + 3}{5 e ^{x}})

\frac{d}{d x} (ln (x^{2} - 2 x + 1))

x \to - 19 lim (13 + x)

\int \frac{x ^{2}}{25 - x ^{2}} d x

\frac{d}{d x} (x^{y} + y^{x})

What is the solution for (dy)/(dx)-7y=xe^{2x} ?
The solution for (dy)/(dx)-7y=xe^{2x} is y=-(e^{2x}(5x+1))/(25)+c_{1}e^{7x}