What is the derivative of ln(x^2+3x) ?

The derivative of ln(x^2+3x) is (2x+3)/(x^2+3x)

What is the first derivative of ln(x^2+3x) ?

The first derivative of ln(x^2+3x) is (2x+3)/(x^2+3x)

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Popular >

\frac{d}{d x} (ln (x^{2} + 3 x))

\frac{2 x + 3}{x ^{2} + 3 x}

Solution steps

\frac{d}{d x} (ln (x^{2} + 3 x))

Apply the chain rule:

\frac{1}{x ^{2} + 3 x} \frac{d}{d x} (x^{2} + 3 x)

= \frac{1}{x ^{2} + 3 x} \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= \frac{1}{x ^{2} + 3 x} (2 x + 3)

Simplify

\frac{1}{x ^{2} + 3 x} (2 x + 3) : \frac{2 x + 3}{x ^{2} + 3 x}

= \frac{2 x + 3}{x ^{2} + 3 x}

\frac{d}{d x} (5 (1 - e^{- 2 x}))

\frac{d}{d x} (x^{2} + y^{2} - 4)

x \to - 1 lim (\frac{x ^{2} + 1}{x + 1})

\int 6 x - x^{2} - 8 d x

\int x sin (\frac{1}{8} x) d x

What is the derivative of ln(x^2+3x) ?
The derivative of ln(x^2+3x) is (2x+3)/(x^2+3x)
What is the first derivative of ln(x^2+3x) ?
The first derivative of ln(x^2+3x) is (2x+3)/(x^2+3x)