What is the solution for e^{x+y}dx+e^{x-y}dy=0 ?

The solution for e^{x+y}dx+e^{x-y}dy=0 is y=-(ln(2x-c_{1}))/2

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e^{x+y}dx+e^{x-y}dy=0

e^{x + y} d x + e^{x - y} d y = 0

y = - \frac{ln ( 2 x - c _{1} )}{2}

Solution steps

e^{x + y} d x + e^{x - y} d y = 0

Solve separable ODE:

y = - \frac{ln ( 2 x - c _{1} )}{2}

y = - \frac{ln ( 2 x - c _{1} )}{2}

f (x) = \frac{x ^{2}}{x + 7}

f (x) = \frac{3 x ^{2}}{ln ( x )}

\int \frac{x ^{3}}{( 6 - x ^{4} ) ^{2}} d x

\int \frac{7 x ^{2} + 16 x - 19}{x ^{2} + 2 x - 3} d x

f (x) = \frac{1}{3 ( x ) ^{2} + 2 ( x )}

What is the solution for e^{x+y}dx+e^{x-y}dy=0 ?
The solution for e^{x+y}dx+e^{x-y}dy=0 is y=-(ln(2x-c_{1}))/2