What is the f(x)=(3x^2)/(ln(x)) ?

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f(x)=(3x^2)/(ln(x))

f (x) = \frac{3 x ^{2}}{ln ( x )}

Domain : 0 < x < 1 or x > 1

Range : f (x) < 0 or f (x) \geq 6 e

Intercepts : None

Asymptotes : Vertical x = 1

Extreme Points : Minimum (e, 6 e)

Interval Notation

Domain : (0, 1) \cup (1, \infty)

Range : (- \infty, 0) \cup [6 e, \infty)

Solution steps

Domain of

\frac{3 x ^{2}}{ln ( x )} : 0 < x < 1 or x > 1

Range of

\frac{3 x ^{2}}{ln ( x )} : f (x) < 0 or f (x) \geq 6 e

Axis interception points of

\frac{3 x ^{2}}{ln ( x )} :

None

Asymptotes of

\frac{3 x ^{2}}{ln ( x )} :

Vertical

: x = 1

Extreme Points of

\frac{3 x ^{2}}{ln ( x )} :

Minimum

(e, 6 e)

\int \frac{x ^{3}}{( 6 - x ^{4} ) ^{2}} d x

\int \frac{7 x ^{2} + 16 x - 19}{x ^{2} + 2 x - 3} d x

f (x) = \frac{1}{3 ( x ) ^{2} + 2 ( x )}

f (x) = 2 x^{3} + 42 x^{2} + 288 x + 14

y = 2 - 6 x