What is the tangent of y=sqrt(2-6x) ?

The tangent of y=sqrt(2-6x) is y=-3/(sqrt(2-6a_{0))}x+sqrt(2-6a_{0)}+(3a_{0})/(sqrt(2-6a_{0))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=sqrt(2-6x)

tangent of

y = 2 - 6 x

y = - \frac{3}{2 - 6 a _{0}} x + 2 - 6 a_{0} + \frac{3 a _{0}}{2 - 6 a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 - 6 a_{0})

Find the slope of

y = 2 - 6 x : \frac{d y}{d x} = - \frac{3}{2 - 6 x}

Compute the slope of

y = 2 - 6 x

x = a_{0} : m = - \frac{3}{2 - 6 a _{0}}

Find the line with slope m=

- \frac{3}{2 - 6 a _{0}}

and passing through

(a_{0}, 2 - 6 a_{0}) : y = - \frac{3}{2 - 6 a _{0}} x + 2 - 6 a_{0} + \frac{3 a _{0}}{2 - 6 a _{0}}

y = - \frac{3}{2 - 6 a _{0}} x + 2 - 6 a_{0} + \frac{3 a _{0}}{2 - 6 a _{0}}

\int (3 + x)^{2} d x

f (x) = - x^{2}

x \to 7 lim (\frac{3}{x - 7})

x \to 0 lim (\frac{3 x}{x ^{2} + 2 x})

\frac{2}{x}

What is the tangent of y=sqrt(2-6x) ?
The tangent of y=sqrt(2-6x) is y=-3/(sqrt(2-6a_{0))}x+sqrt(2-6a_{0)}+(3a_{0})/(sqrt(2-6a_{0))}