What is the tangent of 2/x ?

The tangent of 2/x is y=-2/(a_{0)^2}x+4/(a_{0)}

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tangent of 2/x

tangent of

\frac{2}{x}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}})

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

x = a_{0} : m = - \frac{2}{a _{0}^{2}}

Find the line with slope m=

- \frac{2}{a _{0}^{2}}

and passing through

(a_{0}, \frac{2}{a _{0}}) : y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

\frac{\partial}{\partial x} (4 - x)

\int f (g (x))

\int_{0}^{2} \frac{1}{x} d x

\frac{d}{d x} (sin^{n} (x))

\frac{d}{d x} (ln (\frac{( x - 1 )}{x + 1}))