What is the derivative of 14xe^x ?

The derivative of 14xe^x is 14(e^x+e^xx)

What is the first derivative of 14xe^x ?

The first derivative of 14xe^x is 14(e^x+e^xx)

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\frac{d}{d x} (14 x e^{x})

14 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (14 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 14 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 14 (1 \cdot e^{x} + e^{x} x)

Simplify

= 14 (e^{x} + e^{x} x)

\frac{\partial}{\partial x} (4 ln (x + z))

\int (x + 5) (x - 3) d x

\frac{d}{d x} (2 e^{c o s (x)})

\int x^{6} (x + 4) d x

n = 1 \sum \infty \frac{n}{n + 2}

What is the derivative of 14xe^x ?
The derivative of 14xe^x is 14(e^x+e^xx)
What is the first derivative of 14xe^x ?
The first derivative of 14xe^x is 14(e^x+e^xx)