What is the tangent of f(x)=sqrt(5x+6),(6,6) ?

The tangent of f(x)=sqrt(5x+6),(6,6) is y= 5/12 x+7/2

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tangent of f(x)=sqrt(5x+6),(6,6)

tangent of

f (x) = 5 x + 6, (6, 6)

y = \frac{5}{12} x + \frac{7}{2}

Solution steps

Find the slope of

f (x) = 5 x + 6 : \frac{df ( x )}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

f (x) = 5 x + 6

(6, 6) : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(6, 6) : y = \frac{5}{12} x + \frac{7}{2}

y = \frac{5}{12} x + \frac{7}{2}

\int (tan (3 x) + cot (3 x))^{2} d x

n = 0 \sum \infty \frac{5 ^{n}}{3 ^{n}}

\frac{s}{s - 1}

\int (1 - 8 x) (ln (x) + 1) d x

6 x^{2} + x y + 6 y^{2} = 13, (1, 1)

What is the tangent of f(x)=sqrt(5x+6),(6,6) ?
The tangent of f(x)=sqrt(5x+6),(6,6) is y= 5/12 x+7/2