What is the sum from n=0 to infinity of (-1/2)^n ?

The sum from n=0 to infinity of (-1/2)^n is converges

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sum from n=0 to infinity of (-1/2)^n

n = 0 \sum \infty (- \frac{1}{2})^{n}

converges

Solution steps

n = 0 \sum \infty (- \frac{1}{2})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial y} (2 x y^{3})

y^{^{''}} - 8 y^{^{'}} + 16 y = 2 t e^{4 t}

e^{- \frac{x}{2}}, 3

k = 1 \sum \infty \frac{x ^{k}}{k !}

\frac{d}{d x} (\frac{- 3 x ^{6} - x ^{5} + 3 x ^{4}}{x ^{2}})

What is the sum from n=0 to infinity of (-1/2)^n ?
The sum from n=0 to infinity of (-1/2)^n is converges