What is the derivative of 2-y-2x ?

The derivative of 2-y-2x is -(dy)/(dx)-2

What is the first derivative of 2-y-2x ?

The first derivative of 2-y-2x is -(dy)/(dx)-2

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\frac{d}{d x} (2 - y - 2 x)

- \frac{d y}{d x} - 2

Solution steps

\frac{d}{d x} (2 - y - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d y}{d x} - \frac{d}{d x} (2 x)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (2 x) = 2

= 0 - \frac{d y}{d x} - 2

Simplify

= - \frac{d y}{d x} - 2

x \to - 2 lim (x (- 2))

f (x) = (\frac{x + 4}{x - 4})^{5}

(1 - x^{2}) y^{^{'}} + x y = a x

\frac{d}{d x} (e^{- x} x)

What is the derivative of 2-y-2x ?
The derivative of 2-y-2x is -(dy)/(dx)-2
What is the first derivative of 2-y-2x ?
The first derivative of 2-y-2x is -(dy)/(dx)-2