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Popular >

(1-x^2)y^'+xy=ax

Solution

(1 - x^{2}) y^{^{'}} + x y = a x

Solution

y = - c_{1} 1 - x^{2} + a

Solution steps

(1 - x^{2}) y^{'} (x) + x y = a x

Solve separable ODE:

y = - c_{1} 1 - x^{2} + a

y = - c_{1} 1 - x^{2} + a

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Frequently Asked Questions (FAQ)

What is the solution for (1-x^2)y^'+xy=ax ?
The solution for (1-x^2)y^'+xy=ax is y=-c_{1}sqrt(1-x^2)+a