What is the derivative of 75(1-t/(24))^2 ?

The derivative of 75(1-t/(24))^2 is -25/4 (1-t/(24))

What is the first derivative of 75(1-t/(24))^2 ?

The first derivative of 75(1-t/(24))^2 is -25/4 (1-t/(24))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

75 (1 - \frac{t}{24})^{2}

- \frac{25}{4} (1 - \frac{t}{24})

Solution steps

\frac{d}{d t} (75 (1 - \frac{t}{24})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 75 \frac{d}{d t} ((1 - \frac{t}{24})^{2})

Apply the chain rule:

2 (1 - \frac{t}{24}) \frac{d}{d t} (1 - \frac{t}{24})

= 2 (1 - \frac{t}{24}) \frac{d}{d t} (1 - \frac{t}{24})

\frac{d}{d t} (1 - \frac{t}{24}) = - \frac{1}{24}

= 75 \cdot 2 (1 - \frac{t}{24}) (- \frac{1}{24})

Simplify

75 \cdot 2 (1 - \frac{t}{24}) (- \frac{1}{24}) : - \frac{25}{4} (1 - \frac{t}{24})

= - \frac{25}{4} (1 - \frac{t}{24})

\int t sec^{2} (4 t) d t

y = x^{3} (2 x - 1)^{7}

\int x^{8} (x^{9} - 10)^{7} d x

\frac{\partial}{\partial y} (- 5 y z^{4})

\frac{d}{d x} (ln (\frac{4}{x ^{3}}))

What is the derivative of 75(1-t/(24))^2 ?
The derivative of 75(1-t/(24))^2 is -25/4 (1-t/(24))
What is the first derivative of 75(1-t/(24))^2 ?
The first derivative of 75(1-t/(24))^2 is -25/4 (1-t/(24))