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Popular >

xy^'+2y=2ex

Solution

x y^{^{'}} + 2 y = 2 e x

Solution

y = \frac{2 e x}{3} + \frac{c _{1}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = 2 e x

Solve linear ODE:

y = \frac{2 e x}{3} + \frac{c _{1}}{x ^{2}}

y = \frac{2 e x}{3} + \frac{c _{1}}{x ^{2}}

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\frac{d}{d x} (sec^{2} (3 x))

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y^{^{''}} - 2 \cdot y^{^{'}} = sin (x)

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\int_{0}^{24} 9 + 3 x d x

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\frac{d ^{2}}{d x ^{2}} ((x^{2} + 6)^{9})

derivative of (x-1^n)

\frac{d}{d x} ((x - 1)^{n})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+2y=2ex ?
The solution for xy^'+2y=2ex is y=(2ex)/3+(c_{1})/(x^2)