What is the derivative of (x-1^n) ?

The derivative of (x-1^n) is n(x-1)^{n-1}

What is the first derivative of (x-1^n) ?

The first derivative of (x-1^n) is n(x-1)^{n-1}

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\frac{d}{d x} ((x - 1)^{n})

n (x - 1)^{n - 1}

Solution steps

\frac{d}{d x} ((x - 1)^{n})

Apply the chain rule:

n (x - 1)^{n - 1} \frac{d}{d x} (x - 1)

= n (x - 1)^{n - 1} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= n (x - 1)^{n - 1} \cdot 1

Simplify

= n (x - 1)^{n - 1}

y = 9 - 2 x, y = x^{2} - 39

e^{y} y^{^{'}} = (x + e^{y} - 1)

\int x^{2} 7 x + 8 d x

\frac{d}{dd} (a x^{3} + b x^{2} + c x + d)

\int \frac{2}{3} e^{3 x} d x

What is the derivative of (x-1^n) ?
The derivative of (x-1^n) is n(x-1)^{n-1}
What is the first derivative of (x-1^n) ?
The first derivative of (x-1^n) is n(x-1)^{n-1}