What is the derivative of 8pir^2 ?

The derivative of 8pir^2 is 16pir

What is the first derivative of 8pir^2 ?

The first derivative of 8pir^2 is 16pir

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derivative of

8 π r^{2}

16 π r

Solution steps

\frac{d}{d r} (8 π r^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 π \frac{d}{d r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 π 2 r^{2 - 1}

Simplify

= 16 π r

\int sin (6 x) sin (2 x) d x

y^{^{''}} + 6 y^{^{'}} + 8 y = 0

\int x^{- 4} + x^{\frac{1}{3}} d x

s (t) = 3 t + 1

\frac{\partial}{\partial y} (x^{2} yz - x y z^{3})

What is the derivative of 8pir^2 ?
The derivative of 8pir^2 is 16pir
What is the first derivative of 8pir^2 ?
The first derivative of 8pir^2 is 16pir