What is the limit as x approaches 1+of 2^{1/(x-1)} ?

The limit as x approaches 1+of 2^{1/(x-1)} is infinity

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limit as x approaches 1+of 2^{1/(x-1)}

x \to 1 + lim (2^{\frac{1}{x - 1}})

\infty

Solution steps

x \to 1 + lim (2^{\frac{1}{x - 1}})

Apply exponent rules

= x \to 1 + lim (e^{\frac{1}{x - 1} l n (2)})

Apply the Limit Chain Rule:

\infty

= \infty

x (2 y - 3) d x + (x^{2} + 1) d y = 0

x \to 1 lim (7 x + a)

y^{^{'}} = \frac{2 y}{x}, y (2) = 4

(2 y^{2} + 6 x) d x + 2 x y d y = 0

\frac{d}{d x} (ln (\frac{x + 6}{x - 6}))

What is the limit as x approaches 1+of 2^{1/(x-1)} ?
The limit as x approaches 1+of 2^{1/(x-1)} is infinity