What is the solution for (2y^2+6x)dx+2xydy=0 ?

The solution for (2y^2+6x)dx+2xydy=0 is y=(sqrt(-2x^3+c_{1)})/x ,y=-(sqrt(-2x^3+c_{1)})/x

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(2y^2+6x)dx+2xydy=0

(2 y^{2} + 6 x) d x + 2 x y d y = 0

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

Solution steps

(2 y^{2} + 6 x) d x + 2 x y d y = 0

Solve Bernoulli ODE:

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

\frac{d}{d x} (ln (\frac{x + 6}{x - 6}))

\int \frac{tan ^{2} ( 7 x )}{csc ( 7 x )} d x

f (x) = x (x - 6)^{2}

\frac{d}{d x} (2 sin (x) + 1)

What is the solution for (2y^2+6x)dx+2xydy=0 ?
The solution for (2y^2+6x)dx+2xydy=0 is y=(sqrt(-2x^3+c_{1)})/x ,y=-(sqrt(-2x^3+c_{1)})/x