What is the derivative of 5e^x+4/(\sqrt[3]{x)} ?

The derivative of 5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

What is the first derivative of 5e^x+4/(\sqrt[3]{x)} ?

The first derivative of 5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

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derivative of

5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{d}{d x} (2 sin (x) + 1)

\frac{\partial}{\partial x} (- \frac{1}{2 x} + \frac{1}{2 x ^{2}})

\frac{d}{d x} (x^{4} sin (3 x))

\int \frac{6}{x + 1} d x

y = x sin (\frac{3}{x})

What is the derivative of 5e^x+4/(\sqrt[3]{x)} ?
The derivative of 5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}
What is the first derivative of 5e^x+4/(\sqrt[3]{x)} ?
The first derivative of 5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}