What is the sum from n=1 to infinity of (6^n)/((4+11^n)) ?

The sum from n=1 to infinity of (6^n)/((4+11^n)) is converges

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sum from n=1 to infinity of (6^n)/((4+11^n))

n = 1 \sum \infty \frac{6 ^{n}}{( 4 + 1 1 ^{n} )}

converges

Solution steps

n = 1 \sum \infty \frac{6 ^{n}}{4 + 1 1 ^{n}}

Apply Series Ratio Test:

converges

= converges

\int \frac{4}{x ^{2} + 25} d x

\frac{6 x}{e ^{x}}

x y^{^{'}} + 6 y = - 35 x cos (x^{7})

\int x^{3} 12 + x^{4} d x

n = 1 \sum \infty (- 1)^{n}

What is the sum from n=1 to infinity of (6^n)/((4+11^n)) ?
The sum from n=1 to infinity of (6^n)/((4+11^n)) is converges