What is the solution for xy^'+6y=-35xcos(x^7) ?

The solution for xy^'+6y=-35xcos(x^7) is y=-(5sin(x^7))/(x^6)+(c_{1})/(x^6)

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xy^'+6y=-35xcos(x^7)

x y^{^{'}} + 6 y = - 35 x cos (x^{7})

y = - \frac{5 sin ( x ^{7} )}{x ^{6}} + \frac{c _{1}}{x ^{6}}

Solution steps

x y^{'} (x) + 6 y = - 35 x cos (x^{7})

Solve linear ODE:

y = - \frac{5 sin ( x ^{7} )}{x ^{6}} + \frac{c _{1}}{x ^{6}}

y = - \frac{5 sin ( x ^{7} )}{x ^{6}} + \frac{c _{1}}{x ^{6}}

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What is the solution for xy^'+6y=-35xcos(x^7) ?
The solution for xy^'+6y=-35xcos(x^7) is y=-(5sin(x^7))/(x^6)+(c_{1})/(x^6)