What is the y= 1/(1+e^{-x)} ?

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y= 1/(1+e^{-x)}

y = \frac{1}{1 + e ^{- x}}

Domain : - \infty < x < \infty

Range : 0 < f (x) < 1

Y Intercepts : (0, \frac{1}{2})

Asymptotes : Horizontal y = 1, y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range : (0, 1)

Solution steps

Domain of

\frac{1}{1 + e ^{- x}} : - \infty < x < \infty

Range of

\frac{1}{1 + e ^{- x}} : 0 < f (x) < 1

Axis interception points of

\frac{1}{1 + e ^{- x}} :

Y Intercepts

: (0, \frac{1}{2})

Asymptotes of

\frac{1}{1 + e ^{- x}} :

Horizontal

: y = 1, y = 0

Extreme Points of

\frac{1}{1 + e ^{- x}} :

None

\frac{\partial}{\partial x} (e^{2 x} sin (2 y))

x \to 2 lim (\frac{x ^{2} - 4}{x + 2})

2 x^{^{''}} - 3 x^{^{'}} + x = 0

\frac{d}{d x} (\frac{( \frac{1}{x} + \frac{1}{x ^{2}} )}{x - 1})

\frac{d y}{d x} = 1 - e^{y - x + 5}