What is the integral of x9^x ?

The integral of x9^x is (9^xx)/(2ln(3))-(9^x)/(4ln^2(3))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x9^x

\int x 9^{x} d x

\frac{9 ^{x} x}{2 ln ( 3 )} - \frac{9 ^{x}}{4 ln ^{2} ( 3 )} + C

Solution steps

\int x \cdot 9^{x} d x

Apply Integration By Parts

: \frac{9 ^{x} x}{2 ln ( 3 )} - \int \frac{9 ^{x}}{2 ln ( 3 )} d x

= \frac{9 ^{x} x}{2 ln ( 3 )} - \int \frac{9 ^{x}}{2 ln ( 3 )} d x

\int \frac{9 ^{x}}{2 ln ( 3 )} d x = \frac{9 ^{x}}{4 ln ^{2} ( 3 )}

= \frac{9 ^{x} x}{2 ln ( 3 )} - \frac{9 ^{x}}{4 ln ^{2} ( 3 )}

Add a constant to the solution

= \frac{9 ^{x} x}{2 ln ( 3 )} - \frac{9 ^{x}}{4 ln ^{2} ( 3 )} + C

\int \frac{1}{26 - x ^{2}} d x

\frac{d}{d x} (\frac{4 x + 2}{x + 1})

\int tan^{5} (5 x) d x

\int \frac{e}{x} + \frac{x}{e} d x

\int sec^{2} (x) cos (x) d x

What is the integral of x9^x ?
The integral of x9^x is (9^xx)/(2ln(3))-(9^x)/(4ln^2(3))+C