What is the integral of sec^2(x)cos(x) ?

The integral of sec^2(x)cos(x) is ln|tan(x)+sec(x)|+C

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integral of sec^2(x)cos(x)

\int sec^{2} (x) cos (x) d x

ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int sec^{2} (x) cos (x) d x

Rewrite using trig identities

= \int sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= ln ∣ tan (x) + sec (x) ∣ + C

y = x^{2} - 1, y = x + 1

\frac{d}{d x} (ln (x^{4} + 27))

\int \frac{1}{9 x ^{3}} d x

\int_{1.5}^{2} \frac{2 x}{3} d x

4 y^{^{''}} + 10 y = 0

What is the integral of sec^2(x)cos(x) ?
The integral of sec^2(x)cos(x) is ln|tan(x)+sec(x)|+C