What is the sum from n=0 to infinity of (2^n)/(n!) ?

The sum from n=0 to infinity of (2^n)/(n!) is converges

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sum from n=0 to infinity of (2^n)/(n!)

n = 0 \sum \infty \frac{2 ^{n}}{n !}

converges

Solution steps

n = 0 \sum \infty \frac{2 ^{n}}{n !}

Apply Series Ratio Test:

converges

= converges

x (x - 2) y^{^{'}} + 2 y = 0

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f (x) = x \cdot cot (x), at x = \frac{π}{4}

What is the sum from n=0 to infinity of (2^n)/(n!) ?
The sum from n=0 to infinity of (2^n)/(n!) is converges