What is the solution for (dx)/(dt)=2x(10-x) ?

The solution for (dx)/(dt)=2x(10-x) is x=(10)/(e^{-20t+c_{1)}+1}

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(dx)/(dt)=2x(10-x)

\frac{d x}{d t} = 2 x (10 - x)

x = \frac{10}{e ^{- 20 t + c_{1}} + 1}

Solution steps

\frac{d x}{d t} = 2 x (10 - x)

Solve Bernoulli ODE:

x = \frac{10}{e ^{- 20 t + c_{1}} + 1}

x = \frac{10}{e ^{- 20 t + c_{1}} + 1}

\frac{\partial}{\partial t} (e^{t} sin (t))

\frac{d}{d x} (3 ln (4 x))

\int_{1}^{3} (4 x - 3)^{2} - (x^{2})^{2} d x

\int \frac{6 x ^{2} + 8}{x ^{3} + 4 x} d x

\frac{d y}{d x} + \frac{1}{x} y = x y^{2}

What is the solution for (dx)/(dt)=2x(10-x) ?
The solution for (dx)/(dt)=2x(10-x) is x=(10)/(e^{-20t+c_{1)}+1}