What is the limit as z approaches-1 of (4z+3)/(2z+1) ?

The limit as z approaches-1 of (4z+3)/(2z+1) is 1

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limit as z approaches-1 of (4z+3)/(2z+1)

z \to - 1 lim (\frac{4 z + 3}{2 z + 1})

1

Solution steps

z \to - 1 lim (\frac{4 z + 3}{2 z + 1})

Plug in the value

z = - 1

= \frac{4 ( - 1 ) + 3}{2 ( - 1 ) + 1}

Simplify

\frac{4 ( - 1 ) + 3}{2 ( - 1 ) + 1} : 1

= 1

5 t^{4}

x^{7} y^{^{'}} = - 8 x^{6} y + cos (2 x)

\int \frac{- 2 a x}{x ^{2} + y ^{2}} d y

\frac{d}{d x} (\frac{1}{2} x^{2} + x^{- 1})

\int x^{2} - 4 x d x

What is the limit as z approaches-1 of (4z+3)/(2z+1) ?
The limit as z approaches-1 of (4z+3)/(2z+1) is 1