What is the tangent of y=x^2-5x+5,(0,5) ?

The tangent of y=x^2-5x+5,(0,5) is y=-5x+5

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tangent of y=x^2-5x+5,(0,5)

tangent of

y = x^{2} - 5 x + 5, (0, 5)

y = - 5 x + 5

Solution steps

Find the slope of

y = x^{2} - 5 x + 5 : \frac{d y}{d x} = 2 x - 5

Compute the slope of

y = x^{2} - 5 x + 5

(0, 5) : m = - 5

Find the line with slope m=

- 5

and passing through

(0, 5) : y = - 5 x + 5

y = - 5 x + 5

x \to 5 lim (lo g_{3} (x - 5))

\int 3 tan^{2} (x) sec (x) d x

a x^{2} + b x + c

\frac{d}{d x} (- 4 cos (4 x))

\frac{\partial}{\partial y} (sin (x) + π cos (y))

What is the tangent of y=x^2-5x+5,(0,5) ?
The tangent of y=x^2-5x+5,(0,5) is y=-5x+5