What is the derivative of x^2-ln(x) ?

The derivative of x^2-ln(x) is 2x-1/x

What is the first derivative of x^2-ln(x) ?

The first derivative of x^2-ln(x) is 2x-1/x

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\frac{d}{d x} (x^{2} - ln (x))

2 x - \frac{1}{x}

Solution steps

\frac{d}{d x} (x^{2} - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 x - \frac{1}{x}

sin (x^{2} + π)

2 x - \frac{1}{2 x}

y = arcsin (x^{4})

\frac{\partial}{\partial x} (\frac{1}{( 1 + x )})

(x^{2} - 3 x + 1) 25 - x^{2}

What is the derivative of x^2-ln(x) ?
The derivative of x^2-ln(x) is 2x-1/x
What is the first derivative of x^2-ln(x) ?
The first derivative of x^2-ln(x) is 2x-1/x