What is the derivative of f(x)=-(16)/(x^3) ?

The derivative of f(x)=-(16)/(x^3) is (48)/(x^4)

What is the first derivative of f(x)=-(16)/(x^3) ?

The first derivative of f(x)=-(16)/(x^3) is (48)/(x^4)

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derivative of

f (x) = - \frac{16}{x ^{3}}

\frac{48}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{16}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 16 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 16 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 16 (- 3 x^{- 3 - 1})

Simplify

- 16 (- 3 x^{- 3 - 1}) : \frac{48}{x ^{4}}

= \frac{48}{x ^{4}}

\frac{d}{d x} (a x^{2} (x - 3) + b x^{4} (ln (\frac{x}{3})))

\int \frac{2 t}{1 - t ^{2}} d t

n = 1 \sum \infty n \cdot 2^{- n}

- 5 t^{2} y^{^{''}} - 2 t y^{^{'}} + 14 y = 0

f (x) = π x

What is the derivative of f(x)=-(16)/(x^3) ?
The derivative of f(x)=-(16)/(x^3) is (48)/(x^4)
What is the first derivative of f(x)=-(16)/(x^3) ?
The first derivative of f(x)=-(16)/(x^3) is (48)/(x^4)