What is the solution for -5t^2y^{''}-2ty^'+14y=0 ?

The solution for -5t^2y^{''}-2ty^'+14y=0 is y=(c_{1})/(t^{7/5)}+c_{2}t^2

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-5t^2y^{''}-2ty^'+14y=0

- 5 t^{2} y^{^{''}} - 2 t y^{^{'}} + 14 y = 0

y = \frac{c _{1}}{t ^{\frac{7}{5}}} + c_{2} t^{2}

Solution steps

- 5 t^{2} y^{''} (t) - 2 t y^{'} (t) + 14 y = 0

Solve linear ODE:

y = \frac{c _{1}}{t ^{\frac{7}{5}}} + c_{2} t^{2}

y = \frac{c _{1}}{t ^{\frac{7}{5}}} + c_{2} t^{2}

f (x) = π x

x^{2} e^{x} - 2 x e^{x} + 5 e^{x}

x \to 0 lim (\frac{x ^{2} + 5 x}{x})

x y^{^{'}} = y + x

\int ∣ 2 x - 3 ∣ d x

What is the solution for -5t^2y^{''}-2ty^'+14y=0 ?
The solution for -5t^2y^{''}-2ty^'+14y=0 is y=(c_{1})/(t^{7/5)}+c_{2}t^2