What is the solution for (dy)/(dx)=x^2y^3 ?

The solution for (dy)/(dx)=x^2y^3 is y=sqrt(-3/(2(x^3+c_{1)))},y=-sqrt(-3/(2(x^3+c_{1)))}

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(dy)/(dx)=x^2y^3

\frac{d y}{d x} = x^{2} y^{3}

y = - \frac{3}{2 ( x ^{3} + c _{1} )}, y = - - \frac{3}{2 ( x ^{3} + c _{1} )}

Solution steps

\frac{d y}{d x} = x^{2} y^{3}

Solve separable ODE:

y = - \frac{3}{2 ( x ^{3} + c _{1} )}, y = - - \frac{3}{2 ( x ^{3} + c _{1} )}

y = - \frac{3}{2 ( x ^{3} + c _{1} )}, y = - - \frac{3}{2 ( x ^{3} + c _{1} )}

y^{^{''}} + 6 y^{^{'}} + 9 y = 3 x + 5, y (0) = 1, y^{^{'}} (0) = - 1

\int_{0}^{1} (x^{3} + x) d x

\int 2 x yz d y

\frac{\partial}{\partial y} (y - \frac{1}{x})

x \to 2 + lim (3)

What is the solution for (dy)/(dx)=x^2y^3 ?
The solution for (dy)/(dx)=x^2y^3 is y=sqrt(-3/(2(x^3+c_{1)))},y=-sqrt(-3/(2(x^3+c_{1)))}