What is (\partial)/(\partial x)(sqrt(14-x^2-4xy)) ?

The answer to (\partial)/(\partial x)(sqrt(14-x^2-4xy)) is -(x+2y)/(sqrt(-x^2-4xy+14))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sqrt(14-x^2-4xy))

\frac{\partial}{\partial x} (14 - x^{2} - 4 x y)

- \frac{x + 2 y}{- x ^{2} - 4 x y + 14}

Solution steps

\frac{\partial}{\partial x} (14 - x^{2} - 4 x y)

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 14 - x ^{2} - 4 x y} \frac{\partial}{\partial x} (14 - x^{2} - 4 x y)

= \frac{1}{2 14 - x ^{2} - 4 x y} \frac{\partial}{\partial x} (14 - x^{2} - 4 x y)

\frac{\partial}{\partial x} (14 - x^{2} - 4 x y) = - 2 x - 4 y

= \frac{1}{2 14 - x ^{2} - 4 x y} (- 2 x - 4 y)

Simplify

\frac{1}{2 14 - x ^{2} - 4 x y} (- 2 x - 4 y) : - \frac{x + 2 y}{- x ^{2} - 4 x y + 14}

= - \frac{x + 2 y}{- x ^{2} - 4 x y + 14}

\int x^{2} 8 x - 7 d x

\int_{1}^{5} \frac{x}{e ^{x}} d x

x^{2} - 6 x

f (x) = \frac{3}{x - 2}

- 4 cos (3 t)

What is (\partial)/(\partial x)(sqrt(14-x^2-4xy)) ?
The answer to (\partial)/(\partial x)(sqrt(14-x^2-4xy)) is -(x+2y)/(sqrt(-x^2-4xy+14))