What is the derivative of (2x^2-1)/(xsqrt(1+x^2)) ?

The derivative of (2x^2-1)/(xsqrt(1+x^2)) is (4x^2+1)/(x^2(1+x^2)sqrt(1+x^2))

What is the first derivative of (2x^2-1)/(xsqrt(1+x^2)) ?

The first derivative of (2x^2-1)/(xsqrt(1+x^2)) is (4x^2+1)/(x^2(1+x^2)sqrt(1+x^2))

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derivative of

\frac{2 x ^{2} - 1}{x 1 + x ^{2}}

\frac{4 x ^{2} + 1}{x ^{2} ( 1 + x ^{2} ) 1 + x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{2} - 1}{x 1 + x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{2} - 1 ) x 1 + x ^{2} - \frac{d}{d x} ( x 1 + x ^{2} ) ( 2 x ^{2} - 1 )}{( x 1 + x ^{2} ) ^{2}}

\frac{d}{d x} (2 x^{2} - 1) = 4 x

\frac{d}{d x} (x 1 + x^{2}) = \frac{2 x ^{2} + 1}{1 + x ^{2}}

= \frac{4 xx 1 + x ^{2} - \frac{2 x ^{2} + 1}{1 + x ^{2}} ( 2 x ^{2} - 1 )}{( x 1 + x ^{2} ) ^{2}}

Simplify

\frac{4 xx 1 + x ^{2} - \frac{2 x ^{2} + 1}{1 + x ^{2}} ( 2 x ^{2} - 1 )}{( x 1 + x ^{2} ) ^{2}} : \frac{4 x ^{2} + 1}{x ^{2} ( 1 + x ^{2} ) 1 + x ^{2}}

= \frac{4 x ^{2} + 1}{x ^{2} ( 1 + x ^{2} ) 1 + x ^{2}}

(x - 1) + (2 x - 2)

\frac{\partial}{\partial x} (x cos (x + 2 y) \cdot 2)

\frac{d}{d x} (x \cdot cos (y))

x \to 0 lim (\frac{cot ( π x ) sin ( x )}{2 sec ( x )})

\int cos (3 t) d t

What is the derivative of (2x^2-1)/(xsqrt(1+x^2)) ?
The derivative of (2x^2-1)/(xsqrt(1+x^2)) is (4x^2+1)/(x^2(1+x^2)sqrt(1+x^2))
What is the first derivative of (2x^2-1)/(xsqrt(1+x^2)) ?
The first derivative of (2x^2-1)/(xsqrt(1+x^2)) is (4x^2+1)/(x^2(1+x^2)sqrt(1+x^2))