What is the tangent of f(x)= 3/x ,(9, 1/3) ?

The tangent of f(x)= 3/x ,(9, 1/3) is y=-1/27 x+2/3

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tangent of f(x)= 3/x ,(9, 1/3)

tangent of

f (x) = \frac{3}{x}, (9, \frac{1}{3})

y = - \frac{1}{27} x + \frac{2}{3}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

(9, \frac{1}{3}) : m = - \frac{1}{27}

Find the line with slope m=

- \frac{1}{27}

and passing through

(9, \frac{1}{3}) : y = - \frac{1}{27} x + \frac{2}{3}

y = - \frac{1}{27} x + \frac{2}{3}

\int (8 x^{3} (2 x^{4} + 4)^{4}) d x

\frac{d}{d x} (\frac{x ^{2}}{9 + 8 x})

x \to 0 lim (x^{4} sin (\frac{1}{x}))

\frac{s + 2}{s + 3}

\frac{d}{d x} (x^{5} + 5 x^{4} - 10 x^{2} + 6)

What is the tangent of f(x)= 3/x ,(9, 1/3) ?
The tangent of f(x)= 3/x ,(9, 1/3) is y=-1/27 x+2/3