What is the solution for (dy)/(dx)=e^{4x-3y},y(0)=2 ?

The solution for (dy)/(dx)=e^{4x-3y},y(0)=2 is y=(ln(3/4 e^{4x}+e^6-3/4))/3

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(dy)/(dx)=e^{4x-3y},y(0)=2

\frac{d y}{d x} = e^{4 x - 3 y}, y (0) = 2

y = \frac{ln ( \frac{3}{4} e ^{4 x} + e ^{6} - \frac{3}{4} )}{3}

Solution steps

\frac{d y}{d x} = e^{4 x - 3 y}

Solve separable ODE:

y = \frac{ln ( \frac{3}{4} e ^{4 x} + e ^{6} - \frac{3}{4} )}{3}

y = \frac{ln ( \frac{3}{4} e ^{4 x} + e ^{6} - \frac{3}{4} )}{3}

\int \frac{sin ^{5} ( x )}{cos ( x )} d x

y = x

\frac{\partial}{\partial s} (t^{2} - 2 s^{2})

\int 7 t^{8} d t

y^{^{''}} + 2 y^{^{'}} + 2 y = 3 cos (t) - sin (t)

What is the solution for (dy)/(dx)=e^{4x-3y},y(0)=2 ?
The solution for (dy)/(dx)=e^{4x-3y},y(0)=2 is y=(ln(3/4 e^{4x}+e^6-3/4))/3