What is the integral of 9cos(θ) ?

The integral of 9cos(θ) is 9sin(θ)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9cos(θ)

\int 9 cos (θ) d θ

9 sin (θ) + C

Solution steps

\int 9 cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= 9 sin (θ)

Add a constant to the solution

= 9 sin (θ) + C

\frac{d}{d x} (- 2 x^{2} + 7 x + 5)

n = 0 \sum \infty ln (1 + n)

\frac{\partial}{\partial y} (x^{y} - y^{x})

y = (x^{2} - 7 x + 7) e^{\frac{9 x}{7}}

\int_{0}^{\infty} cos (x) d x